A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?

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#### Solution

Let OB be the pole and AB be the wire.

By Pythagoras theorem,

AB^{2} = OB^{2} + OA^{2}

(24m)^{2} = (18m)^{2} + OA^{2}

OA^{2} = (576 - 324)m^{2} = 25 m^{2}

OA^{2} = `sqrt252 `

Therefore, the distance from the base is `6sqrt7 m`

Concept: Right-angled Triangles and Pythagoras Property

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